Factorizations of numbers of shape 100n + 3·10n + 43

Let P(X) := X^2 + X + 41 (Euler's polynomial).
Substituting X := 10^n + 1, we get the series 100^n + 3·10^n + 43.

Last update

September 5, 2009

Sequence and Limitations

100^n + 3·10^n + 43 with n ≤ 100

Contributors

Robert Backstrom, Kurt Beschorner and Alfred Reich

Factorizations

Copyright (C) 2009 by Alfred Reich. All Rights Reserved.